Let be elements in a commutative ring . Use
to denote the equivalence class of in .
Then firstly we have:
<p>and with that result it can be seen that:</p>
The third isomorphism theorem:
Third isomorphism theorem for rings.
Let be a ring. Let and be ideals of , with
being a "smaller" ring contained within . Then:
- is an ideal of
And really, it's the general case that one should commit to intuition:
Isomorphism theorem for rings (general)
Let and be a rings, and let
be a ring homomorphism. induces an ideal
. Consider two-sided ideals contained in
. Let
be one of these ideals. Then there is a ring homomorphism
fully determined by and such
that the following diagram commutes:
is defined as: