Math and science::Algebra::Aluffi
Two new rings from polynomial ring quotients
Using the below theorem:
- 1. Polynomial evaluation
-
There is a \( f(x) \) so that \( \varphi : R[x] \to R[x]/(f(x)) \) sends any polynomial \( g(x) \) to \( g(a) \).
- [What is \( f(x) \)?]
- [What is \( R[x]/(f(x)) \)?]
- [Is \( \varphi \) an isomorphism of groups or rings?]
- 2. Complex ring, \( \mathbb{C} \)
-
There is a \( f(x) \) so that \( \varphi : R[x] \to R[x]/(f(x)) \) makes \( R[x]/(f(x)) \) isomorphic to \( \mathbb{C} \) as a ring.
- What is \( f(x) \)? \( f(x) = x^2 +1 \)
- How is the multiplication operation transferred to \( R[x]/(f(x)) \)? See below.
Let \( R \) be a commutative ring, \( R[x] \) a polynomial ring, and \( f(x) \in R[x] \) a polynomial. Let \( \varphi: R[x] \to R^{\bigoplus d} \) be a set function defined by by sending \( g(x) \in R[x] \) to the tuple representation of the remainder of \( g(x) \) when divided by \( f(x) \).
Then this function induces an isomorphism of abelian groups:
\[\frac{R[x]}{(f(x))} \cong R^{\bigoplus d}
\]